![]() Since the discriminant is 0, there is 1 real solution to the equation. Since the discriminant is negative, there are 2 complex solutions to the equation.Ī = 9, b = −6, c = 1 a = 9, b = −6, c = 1 Since the discriminant is positive, there are 2 real solutions to the equation.Ī = 5, b = 1, c = 4 a = 5, b = 1, c = 4 ![]() Now we will solve the equation x2 9 again, this time using the Square Root Property. On multiplying whole equation by x x, you get 1 + 2x2 3x 1 + 2 x 2 3 x 2x2 3x + 1 0 2 x 2 3 x + 1 0. We read this as x equals positive or negative the square root of k. So, you can multiply the equation by x x. The equation is in standard form, identify a, b, and c.Ī = 3, b = 7, c = −9 a = 3, b = 7, c = −9 We could also write the solution as x ± k. To determine the number of solutions of each quadratic equation, we will look at its discriminant. The left side is a perfect square, factor it.Īdd − b 2 a − b 2 a to both sides of the equation.ĭetermine the number of solutions to each quadratic equation.
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